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Add day 18 part 2 solution
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2 changed files with 98 additions and 26 deletions
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@ -40,3 +40,32 @@ At the time the recover operation is executed, the frequency of the last sound p
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What is the value of the recovered frequency (the value of the most recently played sound) the first time a rcv instruction is executed with a non-zero value?
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--- Part Two ---
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As you congratulate yourself for a job well done, you notice that the documentation has been on the back of the tablet this entire time. While you actually got most of the instructions correct, there are a few key differences. This assembly code isn't about sound at all - it's meant to be run twice at the same time.
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Each running copy of the program has its own set of registers and follows the code independently - in fact, the programs don't even necessarily run at the same speed. To coordinate, they use the send (snd) and receive (rcv) instructions:
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snd X sends the value of X to the other program. These values wait in a queue until that program is ready to receive them. Each program has its own message queue, so a program can never receive a message it sent.
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rcv X receives the next value and stores it in register X. If no values are in the queue, the program waits for a value to be sent to it. Programs do not continue to the next instruction until they have received a value. Values are received in the order they are sent.
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Each program also has its own program ID (one 0 and the other 1); the register p should begin with this value.
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For example:
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snd 1
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snd 2
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snd p
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rcv a
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rcv b
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rcv c
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rcv d
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Both programs begin by sending three values to the other. Program 0 sends 1, 2, 0; program 1 sends 1, 2, 1. Then, each program receives a value (both 1) and stores it in a, receives another value (both 2) and stores it in b, and then each receives the program ID of the other program (program 0 receives 1; program 1 receives 0) and stores it in c. Each program now sees a different value in its own copy of register c.
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Finally, both programs try to rcv a fourth time, but no data is waiting for either of them, and they reach a deadlock. When this happens, both programs terminate.
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It should be noted that it would be equally valid for the programs to run at different speeds; for example, program 0 might have sent all three values and then stopped at the first rcv before program 1 executed even its first instruction.
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Once both of your programs have terminated (regardless of what caused them to do so), how many times did program 1 send a value?
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@ -2,6 +2,10 @@ use std::fs::File;
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use std::io::{BufRead, BufReader};
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use std::str::FromStr;
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use std::collections::HashMap;
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use std::sync::mpsc::{channel, Sender, Receiver, RecvTimeoutError};
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use std::thread;
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use std::sync::Arc;
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use std::time::Duration;
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type Register = char;
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@ -78,32 +82,36 @@ impl Program {
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// TODO: Machine executes programs and instructions
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#[derive(Debug)]
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struct Machine {
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pid: usize,
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registers: HashMap<char, isize>,
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pc: isize,
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last_played: isize,
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last_received: isize,
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send_count: usize,
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}
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impl Machine {
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pub fn new() -> Machine {
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pub fn new(pid: usize) -> Machine {
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let mut registers = HashMap::new();
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registers.insert('p', pid as isize);
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Machine {
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registers: HashMap::new(),
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pid,
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registers,
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pc: 0,
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last_played: 0,
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last_received: 0,
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send_count: 0,
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}
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}
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pub fn run(&mut self, program: &Program) {
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pub fn run(&mut self, program: &Program, send: Sender<isize>, recv: Receiver<isize>) {
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loop {
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if self.pc < 0 || self.pc >= program.0.len() as isize {
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println!("pid {}: send_count = {}", self.pid, self.send_count);
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break;
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}
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let instruction = &program.0[self.pc as usize];
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self.execute(instruction);
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if self.last_received != 0 {
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// println!("pid {}: {:?}", self.pid, instruction);
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if let Err(_err) = self.execute(instruction, &send, &recv) {
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println!("pid {}: send_count = {}", self.pid, self.send_count);
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break;
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}
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}
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@ -117,15 +125,10 @@ impl Machine {
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self.registers.insert(register, value);
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}
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fn execute(&mut self, instruction: &Instruction) {
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fn execute(&mut self, instruction: &Instruction, send: &Sender<isize>, recv: &Receiver<isize>) -> Result<(), RecvTimeoutError> {
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use Instruction::*;
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// TODO; Increment pc
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match *instruction {
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Snd(ref op) => {
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self.last_played = op.value(self);
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}
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Set(Operand::Register(reg), ref val) => {
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let value = val.value(self);
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self.set(reg, value);
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@ -145,11 +148,16 @@ impl Machine {
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let value = val.value(self);
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self.set(reg, reg_value % value);
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}
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Rcv(ref op) => {
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Snd(ref op) => {
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let value = op.value(self);
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if value != 0 {
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self.last_received = self.last_played;
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}
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send.send(value).expect("error sending");
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self.send_count += 1;
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// println!("pid {}: sent {}", self.pid, value);
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}
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Rcv(Operand::Register(reg)) => {
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let value = recv.recv_timeout(Duration::from_secs(5))?;
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// println!("pid {}: recv {}", self.pid, value);
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self.set(reg, value);
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}
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Jgz(_, _) => { /* handled below */ }
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_ => panic!("bad argument")
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@ -161,7 +169,7 @@ impl Machine {
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let x_value = x.value(self);
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let offset_value = offset.value(self);
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if x_value != 0 {
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if x_value > 0 {
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self.pc += offset_value;
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}
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else {
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@ -170,14 +178,49 @@ impl Machine {
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}
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_ => self.pc += 1
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};
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Ok(())
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}
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}
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fn main() {
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let program = Program::load("input");
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let mut machine = Machine::new();
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fn run(program: Program) {
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let program = Arc::new(program);
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let mut machine0 = Machine::new(0);
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let mut machine1 = Machine::new(1);
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machine.run(&program);
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let (send0, recv1) = channel();
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let (send1, recv0) = channel();
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println!("{:?}", machine);
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let program0 = Arc::clone(&program);
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let thread0 = thread::spawn(move || {
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machine0.run(&program0, send0, recv0);
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});
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let program1 = Arc::clone(&program);
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let thread1 = thread::spawn(move || {
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machine1.run(&program1, send1, recv1);
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});
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thread0.join().unwrap();
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thread1.join().unwrap();
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}
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fn main() {
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run(Program::load("input"));
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}
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#[test]
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fn test_part_two() {
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let input = r"snd 1
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snd 2
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snd p
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rcv a
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rcv b
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rcv c
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rcv d";
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let program = input.lines()
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.map(|line| Instruction::new(line.as_ref()))
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.collect::<Vec<Instruction>>();
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run(Program(program));
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}
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